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Question

A ray of light is incident at 60o on a prism of refracting angle 30o. The emerging ray is at an angle 30o with the incident ray. The value of refractive index of the prism is?
  1. 34
  2. 32
  3. 3
  4. 23

A
23
B
34
C
32
D
3
Solution
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The correct option is C 3
angle of prism A is 30
angle of incidence is 60 degree
angle of deviation is 30 degree
i1+i2=A+δ
the angle of emegrance
i2=A+δi1=30+3060=0
'the emergent ray
r1+r2=A
i2=0,r2=0
r1=A=300
using snells law
n=sini1sinr1=sin60sin30=1.732
since emergent ray is normal
δ=δm=300
sin(30+30/2)sin30/2=1.732

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