A ray of light is incident at 60o on a prism of refracting angle 30o. The emerging ray is at an angle 30o with the incident ray. The value of refractive index of the prism is?
√34
√32
√3
2√3
A
2√3
B
√34
C
√32
D
√3
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Solution
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The correct option is C√3 angle of prism A is 30
angle of incidence is 60 degree
angle of deviation is 30 degree
i1+i2=A+δ
the angle of emegrance
i2=A+δ−i1=30+30−60=0
'the emergent ray
r1+r2=A
i2=0,r2=0
r1=A=300
using snells law
n=sini1sinr1=sin60sin30=1.732
since emergent ray is normal
δ=δm=300
sin(30+30/2)sin30/2=1.732
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