A ray of light is incident an angle i on a glass slab of refractive index mu- The angle between reflected and refracted light is 90-o- Then the relationship between i and mu is-i-tan-1-left - dfrac-1-mu- right -tan i -musin i-mucos i- mu

Question

Toppr Admin · Accepted Answer

Let the angle of reflection and refraction be $r_{1}, r_{2}$ respectively.

Since angle between reflected and refracted ray is $90^{\circ}$ ,
$r_{1} + r_{2} = 90^{\circ}$ .

From law of reflection, $r_{1} = i$

From Snell's law,

$s i n i = μ s i n r_{2}$

$= μ s i n (90^{\circ} - r_{1})$

$= μ c o s r_{1} = μ c o s i$

$⟹ t a n i = μ$

A ray of light is incident at an angle i on a glass slab of refractive index μ. The angle between reflected and refracted light is 90o. Then the relationship between i and μ is.i=tan−1(1μ)tani=μsini=μcosi=μ

Let the angle of reflection and refraction be r1,r2 respectively.Since angle between reflected and refracted ray is 90∘, r1+r2=90∘.From law of reflection, r1=iFrom Snell's law,sini=μsinr2=μsin(90∘−r1)=μcosr1=μcosi⟹tani=μ

A ray of light is incident at an angle i on a glass slab of refractive index $μ$ . The angle between reflected and refracted light is $90^{o}$ . Then the relationship between i and $μ$ is.
$i = t a n^{- 1} (\frac{1}{μ})$
$t a n i = μ$
$s i n i = μ$
$c o s i = μ$