A ray of light is incident an angle of 60-circ-on one of the faces of a prism which has an angle of 30-circ- The ray emerging out of prism makes an angle of 30-circ- with the incident ray- The refractive index of material is1-11-331-51-732

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Toppr Admin · Accepted Answer

-x3B4-30-x2218-A-30-x2218- i1-60-x2218-x3B4-i1-i2-x2212-A30-60-i2-x2212-30-x21D2-i2-0-x21D2-r2-0r1-30-x3BC-xD7-sinr1-sini-x3BC-xD7-12-x221A-32-x3BC-1-732

A ray of light is incident at an angle of 60 $^{\circ}$ on one of the faces of a prism which has an angle of 30 $^{\circ}$ . The ray emerging out of prism makes an angle of 30 $^{\circ}$ with the incident ray. The refractive index of material is
$1.1$
$1.33$
$1.5$
$1.732$

$δ = 30^{\circ} A = 30^{\circ}$ $i_{1} = 60^{\circ}$

$δ = (i_{1} + i_{2}) - A$

$30 = 60 + i_{2} - 30$

$\Rightarrow i_{2} = 0$

$\Rightarrow r_{2} = 0$

$r_{1} = 30$

$μ \times s i n r_{1} = s i n i$

$μ \times \frac{1}{2} = \frac{\sqrt{3}}{2}$

$μ = 1.732$

A ray of light is incident at an angle of 60∘on one of the faces of a prism which has an angle of 30∘. The ray emerging out of prism makes an angle of 30∘ with the incident ray. The refractive index of material is1.11.331.51.732

δ=30∘A=30∘ i1=60∘δ=(i1+i2)−A30=60+i2−30⇒i2=0⇒r2=0r1=30μ×sinr1=siniμ×12=√32μ=1.732

A ray of light is incident at an angle of 60 $^{\circ}$ on one of the faces of a prism which has an angle of 30 $^{\circ}$ . The ray emerging out of prism makes an angle of 30 $^{\circ}$ with the incident ray. The refractive index of material is
$1.1$
$1.33$
$1.5$
$1.732$

$δ = 30^{\circ} A = 30^{\circ}$ $i_{1} = 60^{\circ}$

$δ = (i_{1} + i_{2}) - A$

$30 = 60 + i_{2} - 30$

$\Rightarrow i_{2} = 0$

$\Rightarrow r_{2} = 0$

$r_{1} = 30$

$μ \times s i n r_{1} = s i n i$

$μ \times \frac{1}{2} = \frac{\sqrt{3}}{2}$

$μ = 1.732$