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- The angle of emergence Θ2 of the ray is sin−1(58)
- The angle of emergence Θ2 of the ray is sin−1(73√4)
- Total internal reflection will not occur at P if the refractive index of water increases to a value greater than 52√3 by dissolving some substance
- The angle of emergence Θ2 of the ray is sin−1(54√3)

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Solution

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53sin300=43sinΘ2

⇒sinΘ2=58⇒Θ2=sin−1(58)

If μw>52√3⇒sinC>5/2√32/3⇒C>600

Therefore, now TIR will not occur at P

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