A ray of light is incident normally on one of the faces of a prism of apex angle $30^{o}$ and refractive index $2$ . The angle of deviation of the ray is

Question

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Answer 1

Using geometry in the figure, we get incident angle at prism face AC $i = 3 0^{o}$

Snell's law at P : $μ$ $s i n i = 1 \times s i n r$

$∴$ $2 \times s i n 3 0^{o} = s i n r$ $⟹ r = s i n^{- 1} (\frac{1}{2}) = 4 5^{o}$

Thus deviation of ray: $δ = r - i = 4 5^{o} - 3 0^{o} = 1 5^{o}$

Answer 2

Using geometry in the figure, we get incident angle at prism face AC

i = 3 0^{o}

Snell's law at P :

μ

s i n i = 1 \times s i n r

∴

2 \times s i n 3 0^{o} = s i n r

⟹ r = s i n^{- 1} (\frac{1}{2}) = 4 5^{o}

Thus deviation of ray:

δ = r - i = 4 5^{o} - 3 0^{o} = 1 5^{o}

A ray of light is incident normally on one of the faces of a prism of apex angle $30^{o}$ and refractive index $2$ . The angle of deviation of the ray is

$0^{o}$

$12.5^{o}$

$15^{o}$

$22.5^{o}$

Using geometry in the figure, we get incident angle at prism face AC $i = 3 0^{o}$

Snell's law at P : $μ$ $s i n i = 1 \times s i n r$

$∴$ $2 \times s i n 3 0^{o} = s i n r$ $⟹ r = s i n^{- 1} (\frac{1}{2}) = 4 5^{o}$

Thus deviation of ray: $δ = r - i = 4 5^{o} - 3 0^{o} = 1 5^{o}$

A ray of light incident normally on the horizontal face of the slab and just fail to emerge from the diagonal face of the prism. If prism angle is $3 0^{o}$ then refractive index of the prism can be

Light falls at normal incidence on one face of a glass prism of refractive index $2$ . Then the angle of emergence when the angle of the prism is 45 $^{\circ}$

A ray of light is incident normally on one face of a prism as shown in figure. The refractive index of the material of the prism is $\frac{5}{3}$ and the prism is immersed in water of refractive index $\frac{4}{3}$ then

A prism having an apex angle of $4^{0}$ and refractive index of 1.50 is located in front of a vertical plane mirror as shown.A horizontal ray of light is incident on the prism. The total angle through which the ray is deviated is:

A ray of light is incident normally on one face of a $3 0^{o} - 6 0^{o} - 9 0^{o}$ prism of refractive index $\frac{5}{3}$ immersed in water of refractive index $\frac{4}{3}$ as shown.

Revise with Concepts

Refraction Through Prism

Deviation Produced by a Triangular Prism

Relation Between Angle of Prism and Angle of Deviation, Refractive Index of Materials

Minimum Deviation in a Triangular Prism

Deviation in Reflection, Refraction and Prism

Problems on Tir in Prism

A ray of light is incident normally on one of the faces of a prism of apex angle 30o and refractive index 2​. The angle of deviation of the ray is

0o

12.5o

15o

22.5o

Using geometry in the figure, we get incident angle at prism face AC i=30o Snell's law at P : μ sini=1×sinr ∴ 2​×sin30o=sinr ⟹r=sin−1(2​1​)=45o Thus deviation of ray: δ=r−i=45o−30o=15o

A ray of light incident normally on the horizontal face of the slab and just fail to emerge from the diagonal face of the prism. If prism angle is 30o then refractive index of the prism can be

Light falls at normal incidence on one face of a glass prism of refractive index 2​. Then the angle of emergence when the angle of the prism is 45∘

A ray of light is incident normally on one face of a prism as shown in figure. The refractive index of the material of the prism is 35​ and the prism is immersed in water of refractive index 34​ then

A prism having an apex angle of 40 and refractive index of 1.50 is located in front of a vertical plane mirror as shown.A horizontal ray of light is incident on the prism. The total angle through which the ray is deviated is:

A ray of light is incident normally on one face of a 30o−60o−90o prism of refractive index 35​ immersed in water of refractive index 34​ as shown.

Revise with Concepts

Refraction Through Prism

Deviation Produced by a Triangular Prism

Relation Between Angle of Prism and Angle of Deviation, Refractive Index of Materials

Minimum Deviation in a Triangular Prism

Deviation in Reflection, Refraction and Prism

Problems on Tir in Prism

A ray of light is incident normally on one of the faces of a prism of apex angle $30^{o}$ and refractive index $2$ . The angle of deviation of the ray is

$0^{o}$

$12.5^{o}$

$15^{o}$

$22.5^{o}$

Using geometry in the figure, we get incident angle at prism face AC $i = 3 0^{o}$

Snell's law at P : $μ$ $s i n i = 1 \times s i n r$

$∴$ $2 \times s i n 3 0^{o} = s i n r$ $⟹ r = s i n^{- 1} (\frac{1}{2}) = 4 5^{o}$

Thus deviation of ray: $δ = r - i = 4 5^{o} - 3 0^{o} = 1 5^{o}$

A ray of light incident normally on the horizontal face of the slab and just fail to emerge from the diagonal face of the prism. If prism angle is $3 0^{o}$ then refractive index of the prism can be

Light falls at normal incidence on one face of a glass prism of refractive index $2$ . Then the angle of emergence when the angle of the prism is 45 $^{\circ}$

A ray of light is incident normally on one face of a prism as shown in figure. The refractive index of the material of the prism is $\frac{5}{3}$ and the prism is immersed in water of refractive index $\frac{4}{3}$ then

A prism having an apex angle of $4^{0}$ and refractive index of 1.50 is located in front of a vertical plane mirror as shown.A horizontal ray of light is incident on the prism. The total angle through which the ray is deviated is:

A ray of light is incident normally on one face of a $3 0^{o} - 6 0^{o} - 9 0^{o}$ prism of refractive index $\frac{5}{3}$ immersed in water of refractive index $\frac{4}{3}$ as shown.