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# A ray of light is incident normally on one of the faces of a prism of apex angle 30o and refractive index √2. The angle of deviation of the ray is 15o0o22.5o12.5o

A
15o
B
0o
C
12.5o
D
22.5o
Solution
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#### Using geometry in the figure, we get incident angle at prism face AC i=30oSnell's law at P : μ sini=1×sinr∴ √2×sin30o=sinr ⟹r=sin−1(1√2)=45oThus deviation of ray: δ=r−i=45o−30o=15o

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