0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# A ray of light is incident on a prism ABC of refractive index √3 as shown in figure.(a) Find the angle of incidence for which the deviation of light ray by the prism ABC is minimum.(b) By what angle the second prism must be rotated, so that the final ray suffer net minimum deviation. 30o, 60o60o, 30o60o, 60oNone of these

A
60o, 60o
B
None of these
C
30o, 60o
D
60o, 30o
Solution
Verified by Toppr

#### Minimum deviationi1=i2=i and r1=r2=rand r1+r2=Ar=A/2=30∘Using Snell's law,sini1sinr1=μsini1=√3sin30∘sini1=√32i1=60∘When the prism is rotated anticlockwise by 60∘ the combined prism will become a slab as shown in the figure 2. In this case the net deviation by the prism will be zero as the deviation by the two prism will be equal and opposite.

Was this answer helpful?
0
Similar Questions
Q1
A ray of light is incident on a prism ABC of refractive index 3 as shown in figure.
(a) Find the angle of incidence for which the deviation of light ray by the prism ABC is minimum.
(b) By what angle the second prism must be rotated, so that the final ray suffer net minimum deviation.

View Solution
Q2
A prism of refractive index 2 has refracting angle of 60o. At what angle a ray must be incident one it so that it suffers a minimum deviation?
View Solution
Q3
A ray of light incident at an angle 48o on a prism refracting angle 60o suffers minimum deviation. Calculate the angle of minimum deviation.
View Solution
Q4
A trihedral with refracting angle 60o deviates a light ray by 30o. the refractive index of the material of prism:
View Solution
Q5
A ray of light is incident at 60o on a prism of refracting angle 30o. The emerging ray is at an angle 30o with the incident ray. The value of refractive index of the prism is?
View Solution