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>> $A ray of light is incident on an equilat$

Question

A ray of light is incident on an equilateral prism in such a way that the angle of incidence is equal to the angle of emergence and each is equal to 3/4 of the prism angle. The angle of deviation for the ray of light is

A

$45^{\circ}$

B

$30^{\circ}$

C

$39^{\circ}$

D

$20^{\circ}$

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Updated on : 2022-09-05

Solution

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Correct option is B)

As angle of incidence is equal to the angle of emergence the prism is set in minimum deviation position

$δ_{m i n} = i_{i} + i_{e} - A = \frac{3}{4} (60 + 60) - 60 = 3 0^{o}$ .

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