A ray of light is travelling inside a rectangular glass block of refractive index $\sqrt{2}$ and incidents on glass-air interface at an angle of incidence 45 $^{\circ}$ . Under these conditions, the ray
will emerge into air with an angle of deviation $0$ $^{\circ}$
will be reflected back into the medium
will be absorbed
will just graze the surface of seperation of the two media

Question

A ray of light is travelling inside a rectangular glass block of refractive index $\sqrt{2}$ and incidents on glass-air interface at an angle of incidence 45 $^{\circ}$ . Under these conditions, the ray
will emerge into air with an angle of deviation $0$ $^{\circ}$
will be reflected back into the medium
will be absorbed
will just graze the surface of seperation of the two media

Toppr Admin · Accepted Answer

-x3BC-sini-sinr-x221A-2sin45-sinr-gt-r-90-x2218-Therefore the angle of refraction is 90-x2218-So the ray will just graze the surface of separation of the two media-

μsini=sinr√2sin45=sinr=>r=90∘Therefore the angle of refraction is 90∘.So the ray will just graze the surface of separation of the two media.

$μ s i n i = s i n r$

$\sqrt{2} s i n 45 = s i n r$

=> $r = 90^{\circ}$

Therefore the angle of refraction is $90^{\circ}$ .

So the ray will just graze the surface of separation of the two media.