A ray of light passes through an equilateral prism (refractive index 1.5) such that angle of incidence is equal to angle of emergence and the latter is equal to ${3 / 4}^{t h}$ of the angle of prism. The angle of deviation is

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I-e-x2234-r1-r2r1-r2-180-x2212-A-180A-r1-r2r2-r1-A-2sinisinr1-x3BC-x3BC-sin-3A-4-sin-A-2-xA0- -xA0-sin-3-xD7-604-sin-60-2-xA0- -xA0-sin45sin30

A ray of light passes through an equilateral glass prism, such that the angle of incidence is equal to the angle of emergence. If the angle of emergence is $\frac{3}{4}$ times the angle of prism. The refractive index of the glass prism is:

$i = e$
$∴ r_{1} = r_{2}$
$r_{1} + r_{2} + 180 - A = 180$
$A = r_{1} + r_{2}$
$r_{2} = r_{1} = A / 2$

$\frac{s i n i}{s i n r_{1}} = μ$

$μ = \frac{s i n (3 A / 4)}{s i n (A / 2)}$

$= \frac{s i n (\frac{3 \times 60}{4})}{s i n (60 / 2)}$

$= \frac{s i n 45}{s i n 30}$

A ray of light passes through an equilateral glass prism, such that the angle of incidence is equal to the angle of emergence. If the angle of emergence is 34times the angle of prism. The refractive index of the glass prism is:

i=e∴r1=r2r1+r2+180−A=180A=r1+r2r2=r1=A/2sinisinr1=μμ=sin(3A/4)sin(A/2) =sin(3×604)sin(60/2) =sin45sin30

A ray of light passes through an equilateral glass prism, such that the angle of incidence is equal to the angle of emergence. If the angle of emergence is $\frac{3}{4}$ times the angle of prism. The refractive index of the glass prism is:

$i = e$
$∴ r_{1} = r_{2}$
$r_{1} + r_{2} + 180 - A = 180$
$A = r_{1} + r_{2}$
$r_{2} = r_{1} = A / 2$

$\frac{s i n i}{s i n r_{1}} = μ$

$μ = \frac{s i n (3 A / 4)}{s i n (A / 2)}$

$= \frac{s i n (\frac{3 \times 60}{4})}{s i n (60 / 2)}$

$= \frac{s i n 45}{s i n 30}$