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Question

A ray of light passes through an equilateral prism (μ=1.5). The angle of minimum deviation is
  1. 45o
  2. 20o
  3. 30o
  4. 37o12

A
45o
B
20o
C
30o
D
37o12
Solution
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μ=sin(A+δm)/2sinA/2

sin(A+δm)2=μsinA/2=1.5×sin30o=0.75

A+δm2=sin1(0.75)=48o36δm=37o12

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