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Question

# A ray of light passes through an equilateral prism (μ=1.5). The angle of minimum deviation is45o20o30o37o12′

A
20o
B
45o
C
30o
D
37o12
Solution
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#### μ=sin(A+δm)/2sinA/2⇒sin(A+δm)2=μsinA/2=1.5×sin30o=0.75A+δm2=sin−1(0.75)=48o36′∴δm=37o12′

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