A ray of light passes through an equilateral prism (μ=1.5). The angle of minimum deviation is

45o

20o

30o

37o12′

A

20o

B

45o

C

30o

D

37o12′

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Solution

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μ=sin(A+δm)/2sinA/2

⇒sin(A+δm)2=μsinA/2=1.5×sin30o=0.75

A+δm2=sin−1(0.75)=48o36′∴δm=37o12′

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