A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and the latter is equal to ${\frac{3}{4}}^{t h}$ angle of prism. What will be the deviation?

Question

A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and the latter is equal to 34th angle of prism- What will be the deviation-

Toppr Admin · Accepted Answer

I-34AAlso i-A-x3B4-m2-x27F9-A-x3B4-m2-34A-x27F9-A-x3B4-m-1-5A0r -x3B4-m-A2-30o

A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and the latter is equal to 34th angle of prism. What will be the deviation?

i=34AAlso i=A+δm2⟹A+δm2=34A⟹A+δm=1.5A0r δm=A2=30o

A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and the latter is equal to ${\frac{3}{4}}^{t h}$ angle of prism. What will be the deviation?

$i = \frac{3}{4} A$

Also $i = \frac{A + δ_{m}}{2}$

$⟹ \frac{A + δ_{m}}{2} = \frac{3}{4} A$

$⟹ A + δ_{m} = 1.5 A$

0r $δ_{m} = \frac{A}{2} = 30^{o}$