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# A ray of light passing through a prism having μ=√2 suffer minimum deviation. It is found that angle of incidence is double the angle of refraction within the prism. Find angle of the prism.

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#### if ∠i= incidence angle∠r= refracted angle∠i=2×∠rsinisinr=μsin2rsinr=2sinrcosrsinr=2cosr=√2cosr=1√2r=45∘For minimum deviation, r1=r2=r∴a=2×r∠a=2×45∘ =90∘

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