A ray of light passing through a prism having μ=2 suffer minimum deviation. It is found that angle of incidence is double the angle of refraction within the prism. Find angle of the prism.
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Solution
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if ∠i= incidence angle
∠r= refracted angle
∠i=2×∠r
sinrsini=μ
sinrsin2r=sinr2sinrcosr=2cosr=2
cosr=21
r=45∘
For minimum deviation, r1=r2=r
∴a=2×r
∠a=2×45∘
=90∘
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