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Given: refractive index of medium u,

angle of incidence ,θ.

angle of deviation, $$\delta$$

angle of refraction,ϕ .

For θ < c, $$\delta$$ = ϕ - θ with sinϕ / sinθ = μ or ϕ = sin-1 (μsin θ).

For θ < c, $$\delta$$ = ϕ - θ with sinϕ / sinθ = μ or ϕ = sin-1 (μsin θ).

∴ $$\delta$$ = sin-1 (μsin θ) - θ This is a nonlinear relation.

The maximum value of $$\delta$$ is $$\delta$$1 = π/2 - c for θ = c and ϕ = π/2.

For θ > c, $$\delta$$ = π - 2θ $$\delta$$ decreases linearly with θ.

$$\delta$$max = π - 2c = $$\delta$$2 = 2$$\delta$$1.

therefore, $$\delta$$2$$\div$$$$\delta$$1=2.

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