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Correct option is B)

angle of incidence ,θ.

angle of deviation, $δ$

angle of refraction,ϕ .

For θ < c, $δ$ = ϕ - θ with sinϕ / sinθ = μ or ϕ = sin-1 (μsin θ).

For θ < c, $δ$ = ϕ - θ with sinϕ / sinθ = μ or ϕ = sin-1 (μsin θ).

∴ $δ$ = sin-1 (μsin θ) - θ This is a nonlinear relation.

The maximum value of $δ$ is $δ$1 = π/2 - c for θ = c and ϕ = π/2.

For θ > c, $δ$ = π - 2θ $δ$ decreases linearly with θ.

$δ$max = π - 2c = $δ$2 = 2$δ$1.

therefore, $δ$2$÷$$δ$1=2.

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