A ray PQ incident normally on the refracting face BA is refracted in the prism BAC made of material of refractive index 1-5 - Complete the path ray through the prism- From which face will the ray emerge- Justify your answer-

Question

Toppr Admin · Accepted Answer

The incidence angle is given as-sinic-23-sinic-0-66-So- ic-gt-30-x2218-Thus- the light will emerge out from face AC-

A ray $P Q$ incident normally on the refracting face $B A$ is refracted in the prism $B A C$ made of material of refractive index $1.5$ . Complete the path ray through the prism. From which face will the ray emerge? Justify your answer.

The incidence angle is given as,

$sin i_{c} = \frac{2}{3}$

$sin i_{c} = 0.66$

So, $i_{c} > 30^{\circ}$

Thus, the light will emerge out from face AC.

A ray PQ incident normally on the refracting face BA is refracted in the prism BAC made of material of refractive index 1.5 . Complete the path ray through the prism. From which face will the ray emerge? Justify your answer.

The incidence angle is given as, sinic=23 sinic=0.66 So, ic>30∘ Thus, the light will emerge out from face AC.

A ray $P Q$ incident normally on the refracting face $B A$ is refracted in the prism $B A C$ made of material of refractive index $1.5$ . Complete the path ray through the prism. From which face will the ray emerge? Justify your answer.

The incidence angle is given as,

$sin i_{c} = \frac{2}{3}$

$sin i_{c} = 0.66$

So, $i_{c} > 30^{\circ}$

Thus, the light will emerge out from face AC.