A real image is formed by a convex lens. If we put a concave lens in contact with it, the combination again forms a real image. the new image

is closer to the lens system

is farther form the lens system

is at the original position

may be anywhere depending on the focal length of the concave lens.

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Solution

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When we bring in contact a concave lens the effective focal length of the combination decreases.

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \Rightarrow \frac{1}{v} = \frac{1}{u} + \frac{1}{f}$

according to above relation as $f$ reduces, $v$ increases.

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A real image is formed by a convex lens. If we put a concave lens in contact with it, the combination again forms a real image. the new image

When we bring in contact a concave lens the effective focal length of the combination decreases.1v−1u=1f⇒1v=1u+1faccording to above relation as f reduces, v increases.

When we bring in contact a concave lens the effective focal length of the combination decreases.

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \Rightarrow \frac{1}{v} = \frac{1}{u} + \frac{1}{f}$

according to above relation as $f$ reduces, $v$ increases.