A rectangle is inscribed in a square creating four isosceles right angles. If the total area of these four triangles is 200. The length of the diagonal of the rectangle is
10
15
20
25
A
10
B
20
C
25
D
15
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Solution
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Let the square ABCD is divided into 4 triangles . ∴ sum of the area of these triangles = area of square ABCD ∴200=areaofsquareABCD ∴200=(AB)2 ∴AB=10√2cm ∴DiagonalAC=BD=AB×√2=10√2×√2=20cm
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