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Correct option is B)

$τ=NIABsinθ$

where number of turns $N=500$,

Current in the coil $I=2A$,

Area of the coil $A=(10×5)10_{−4}m_{2}$,

Magnetic field $B=2×10_{−3}T$,

Angle between area and magnetic field vector is $θ$

As area vector is always normal to plane and given the plane is parallel to field, so the angle between area and field is $90_{o}$.

So, $τ=500×2×(10×5)×10_{−4}×(2×10_{−3})sin90=0.01Nm$

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