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- sin−1[μ1μ2cos(sin−1(μ2μ1))]
- sin−1[μ1cos(sin−1(1μ2))]
- sin−1(μ1μ2)
- sin−1(μ2μ1)

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Solution

Verified by Toppr

For the ray to emerge from the face CD, it at first must undergo total internal reflection at face AD i-e, r1>θc

r1=sin−1(μ2μ1) .........................(1)

Also from geometry, r=90−r1⟹sinr=cosr1 .............(2)

Snell's law for face AB, μ2sinαmax=μ1 sinr Thus from (1) & (2), μ2 sinαmax=μ1cos(sin−1(μ2μ1))

Thus αmax=sin−1[μ1μ2cos(sin−1(μ2μ1))]

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