A right angled triangle with sides 3-cm-4cm and 5-cm is rotated about the side of 3-cm to form a cone- The volume of the cone so formed is-12pi -c-m-3-15pi -c-m-3-16pi -c-m-3-20pi -c-m-3-

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Toppr Admin · Accepted Answer

So the height of the cone-xA0-will be 3cmAnd radius -4cmv-x3C0-r2h3-x3C0-xD7-16-xD7-33v-16-x3C0-cm3

A right angled triangle with sides $3 c m, 4 c m$ and $5 c m$ is rotated about the side of $3 c m$ to form a cone. The volume of the cone so formed is:
$12 π c m^{3}$
$15 π c m^{3}$
$16 π c m^{3}$
$20 π c m^{3}$

So the height of the cone will be $3 c m$
And radius $= 4 c m$

$v = \frac{π r^{2} h}{3}$

$= \frac{π \times 16 \times 3}{3}$

$v = 16 π c m^{3}$

A right angled triangle with sides 3cm,4cm and 5cm is rotated about the side of 3cm to form a cone. The volume of the cone so formed is:12πcm315πcm316πcm320πcm3

So the height of the cone will be 3cmAnd radius =4cmv=πr2h3=π×16×33v=16πcm3

A right angled triangle with sides $3 c m, 4 c m$ and $5 c m$ is rotated about the side of $3 c m$ to form a cone. The volume of the cone so formed is:
$12 π c m^{3}$
$15 π c m^{3}$
$16 π c m^{3}$
$20 π c m^{3}$

So the height of the cone will be $3 c m$
And radius $= 4 c m$

$v = \frac{π r^{2} h}{3}$

$= \frac{π \times 16 \times 3}{3}$

$v = 16 π c m^{3}$