A right circular cone is 8 text- cm- high- the radius of the base is 6 text- cm- Find the curved surface area314text- cm-2-315text- cm-2-413text- cm-2-431text- cm-2-

Question

Toppr Admin · Accepted Answer

Given-h-8-xA0-cmr-6-xA0-cmCurved surface area -x3C0-rll-x221A-h2-r2-x221A-82-62-x221A-64-36-x221A-100-10-xA0-cm-x2234- Curved surface area -3-14-xD7-10-xD7-10-314-xA0-cm2-

A right circular cone is $8 cm$ high, the radius of the base is $6 cm$ . Find the curved surface area
$314 {cm}^{2}$
$315 {cm}^{2}$
$413 {cm}^{2}$
$431 {cm}^{2}$

Given:
$h = 8 cm$
$r = 6 cm$
Curved surface area $= π r l$
$l = \sqrt{h^{2} + r^{2}}$
$= \sqrt{8^{2} + 6^{2}}$
$= \sqrt{64 + 36} = \sqrt{100}$
$= 10 cm$
$∴$ Curved surface area $= 3.14 \times 10 \times 10 = 314 {cm}^{2}$ .

A right circular cone is 8 cm high, the radius of the base is 6 cm. Find the curved surface area314 cm2315 cm2413 cm2431 cm2

Given:h=8 cmr=6 cmCurved surface area =πrll=√h2+r2=√82+62=√64+36=√100=10 cm∴ Curved surface area =3.14×10×10=314 cm2.

A right circular cone is $8 cm$ high, the radius of the base is $6 cm$ . Find the curved surface area
$314 {cm}^{2}$
$315 {cm}^{2}$
$413 {cm}^{2}$
$431 {cm}^{2}$

Given:
$h = 8 cm$
$r = 6 cm$
Curved surface area $= π r l$
$l = \sqrt{h^{2} + r^{2}}$
$= \sqrt{8^{2} + 6^{2}}$
$= \sqrt{64 + 36} = \sqrt{100}$
$= 10 cm$
$∴$ Curved surface area $= 3.14 \times 10 \times 10 = 314 {cm}^{2}$ .