A right circular cylindrical tunnel of diameter 2 m and length 40 m is to be constructed from a sheet of iron. The area of the iron sheet required in $m^{2}$ , is

(a) 40 $π$ (b) 80 $π$

(c) 160 $π$ (d) 200 $π$

Question

A right circular cylindrical tunnel of diameter 2m and length 40m is to be constructed from a sheet of iron- The area of the iron sheet required in m-2- is-

Toppr Admin · Accepted Answer

Correct option is B- -80-pi-Let -r- be the radius of the cylinder and -h-be its height-It is given that-d-2-m-Then- -r-dfrac-2m-2-1-m-h-40-m-therefore-160- Total surface area of sheet required is-Rightarrow-160- -S-2-pi rh-160- -160- -160- -160- -160- -2-pi-times 1-times 40-160- -160- -160- -160- -160- -80-pi -m-2-

A right circular cylindrical tunnel of diameter $$2$$m and length $$40$$m is to be constructed from a sheet of iron. The area of the iron sheet required in $$m^2$$, is?

Correct option is B. $$80\pi$$
Let $$r$$ be the radius of the cylinder and $$h$$be its height.
It is given that,
$$d=2\,m$$
Then, $$r=\dfrac{2m}{2}=1\,m$$
$$h=40\,m$$
$$\therefore$$ Total surface area of sheet required is:
$$\Rightarrow$$ $$S=2\pi rh$$
$$=2\pi\times 1\times 40$$
$$=80\pi \,m^2$$

A right circular cylindrical tunnel of diameter $$2$$m and length $$40$$m is to be constructed from a sheet of iron. The area of the iron sheet required in $$m^2$$, is?

Correct option is B. $$80\pi$$Let $$r$$ be the radius of the cylinder and $$h$$be its height.It is given that,$$d=2\,m$$Then, $$r=\dfrac{2m}{2}=1\,m$$$$h=40\,m$$$$\therefore$$ Total surface area of sheet required is:$$\Rightarrow$$ $$S=2\pi rh$$ $$=2\pi\times 1\times 40$$ $$=80\pi \,m^2$$

Correct option is B. $$80\pi$$
Let $$r$$ be the radius of the cylinder and $$h$$be its height.
It is given that,
$$d=2\,m$$
Then, $$r=\dfrac{2m}{2}=1\,m$$
$$h=40\,m$$
$$\therefore$$ Total surface area of sheet required is:
$$\Rightarrow$$ $$S=2\pi rh$$
$$=2\pi\times 1\times 40$$
$$=80\pi \,m^2$$