A road roller 4 m wide and with a diameter of 3-5 m makes 4 revolutions in 1 minute- How much time will it take to roll over an area of 6160 m-2-40 min20 min35 min17-5 min

Question

Toppr Admin · Accepted Answer

Area in one revolution -2-x3C0-r-xD7-width-2-x3C0-3-52-xD7-4-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -227-xD7-3510-xD7-4-44m2No- of revolution required to roll area of 6160 m2 -616044-140Time required -1404-35min

A road roller $4$ m wide and with a diameter of $3.5$ m makes $4$ revolutions in $1$ minute. How much time will it take to roll over an area of $6160$ m $^{2}$ ?
$40$ min
$20$ min
$35$ min
$17.5$ min

Area in one revolution $= 2 π r \times w i d t h = 2 π (\frac{3.5}{2}) \times 4$
$= \frac{22}{7} \times \frac{35}{10} \times 4 = 44 m^{2}$
No. of revolution required to roll area of 6160 m $^{2}$ $= \frac{6160}{44} = 140$
Time required $= \frac{140}{4} = 35 m i n$

A road roller 4 m wide and with a diameter of 3.5 m makes 4 revolutions in 1 minute. How much time will it take to roll over an area of 6160 m2?40 min20 min35 min17.5 min

Area in one revolution =2πr×width=2π(3.52)×4 =227×3510×4=44m2No. of revolution required to roll area of 6160 m2 =616044=140Time required =1404=35min

A road roller $4$ m wide and with a diameter of $3.5$ m makes $4$ revolutions in $1$ minute. How much time will it take to roll over an area of $6160$ m $^{2}$ ?
$40$ min
$20$ min
$35$ min
$17.5$ min

Area in one revolution $= 2 π r \times w i d t h = 2 π (\frac{3.5}{2}) \times 4$
$= \frac{22}{7} \times \frac{35}{10} \times 4 = 44 m^{2}$
No. of revolution required to roll area of 6160 m $^{2}$ $= \frac{6160}{44} = 140$
Time required $= \frac{140}{4} = 35 m i n$