A road which is $$7$$ m wide surrounds a circular park whose circumference is $$88 m$$. Find the area of the road.
Given
$$w=7m$$
$$2\pi r=88m$$
$$\Rightarrow 2.\dfrac{22}{7} r=88$$
$$\Rightarrow 2.\dfrac{1}{7}.r=4$$
$$\Rightarrow r=2\times 7$$
$$r=14$$
So, $$r=14$$
$$R=r+w=14+7=21$$
$$\therefore$$ Area of road $$=\pi R^2-\pi r^2$$
$$=\pi (R+r)(R-r)$$
$$=\dfrac{22}{7}(21+14)(21-14)$$
$$=\dfrac{22}{7}(35)(7)$$
$$=770m^2$$