Question

A rocket is moving in a gravity free space with a constant acceleration of $2m{s}^{-2}$ along $+x$ direction (see figure). The length of a chamber inside the rocket is $4m$. A ball is thrown from the left end of the chamber in $+x$ direction with a speed of $0.3m{s}^{-1}$ relative to the rocket. At the same time, another ball is thrown in -x direction with a speed of $0.2m{s}^{-1}$ from its right end relative to the rocket. The time in seconds when the two balls hit each other is

Answer 1

From the reference frame of the rocket the magnitude of the relative velocity of one of the ball
with respect to other is $(0.2+0.3)=0.5m/s$
So time taken $=$ $\frac{RelativeSeparation}{Relativevelocity}=\frac{4}{0.5}=8s$