A rope is wound round a hollow cylinder of mass $3 k g$ and radius $40 c m$ . If the rope is pulled with a force of $30 N$ , the angular acceleration of the cylinder will be:

Question

A rope is wound round a hollow cylinder of mass M and radius R- If the rope is pulled with a force F newton- then the angular acceleration of teh cylinder will be-

Toppr Admin · Accepted Answer

Correct option is B- -F-MR-According to question we have-160-I- Mr-2 -MR-2-Now -tau -F -times R-I -alpha-alpha -dfrac-F -times R-I- -dfrac-FR-MR-2-dfrac-F-MR-

A rope is wound round a hollow cylinder of mass $$M$$ and radius $$R.$$ If the rope is pulled with a force $$F$$ newton, then the angular acceleration of teh cylinder will be:

Correct option is B. $$F/MR$$
According to question we have
$$I= Mr^2 =MR^2$$
Now $$\tau =F \times R=I \alpha$$
$$\alpha =\dfrac{F \times R}{I} =\dfrac{FR}{MR^2}=\dfrac{F}{MR}$$

A rope is wound round a hollow cylinder of mass $$M$$ and radius $$R.$$ If the rope is pulled with a force $$F$$ newton, then the angular acceleration of teh cylinder will be:

Correct option is B. $$F/MR$$According to question we have $$I= Mr^2 =MR^2$$Now $$\tau =F \times R=I \alpha$$$$\alpha =\dfrac{F \times R}{I} =\dfrac{FR}{MR^2}=\dfrac{F}{MR}$$

Correct option is B. $$F/MR$$
According to question we have
$$I= Mr^2 =MR^2$$
Now $$\tau =F \times R=I \alpha$$
$$\alpha =\dfrac{F \times R}{I} =\dfrac{FR}{MR^2}=\dfrac{F}{MR}$$