A satellite in force free space sweeps stationary interplanetary dust at a rate dMdt=αv, where M is the mass and v is the velocity of the satellite and α is a constant. The tangential acceleration of satellite is
−αv22M
−αv2
−αv2M
−2αv2M
A
−αv22M
B
−αv2M
C
−αv2
D
−2αv2M
Open in App
Solution
Verified by Toppr
we know F=ddt(Mv)=Mdvdt+vdMdt=Mdvdt+vαv As, dMdt=αv
Was this answer helpful?
0
Similar Questions
Q1
A satellite in a force free space sweeps stationary interplanetary dust at a rate dMdt=αv, where M is the mass and v is the velocity of the satellite and α is a constant. The acceleration of the satellite is
View Solution
Q2
A satellite in force free space sweeps stationary interplanetary dust at a rate dMdt=αv, where M is the mass and v is the velocity of the satellite and α is a constant. The tangential acceleration of satellite is
View Solution
Q3
A satellite in force-free space sweeps stationary interplanetary dust at a rate of dM/dt=αv, where M is mass and v is the speed of satellite and α is a constant. The tangential acceleration of satellite is
View Solution
Q4
A satellite in a force free space sweeps stationary interplanetary dust at a rate dMdt=αv, where M is the mass and v is the velocity of the satellite and α is a constant. The acceleration of the satellite is
View Solution
Q5
A satellite in force free space sweeps stationary interplanetary dust at a rate (dM/dt)=+αv. The acceleration of satellite of mass M is: