A satellite is seen after each 8 h over the equator a place on the earth when its sense of rotation is opposite to the earth- The time interval after which it can be seen the same place when the sense of rotation of the earth and the satellite is the same will be8 h24 h12 h6 h

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Toppr Admin · Accepted Answer

The time period is given by-T-2-x3C0-x3C9-Angular Velocity is given by-x3C9-2-x3C0-Tand then find relative angular velocityGiven 8-2-x3C0-x3C9-1-x3C9-2-2-x3C0-2-x3C0-T1-2-x3C0-T2

A satellite is seen after each $8 h$ over the equator at a place on the earth when its sense of rotation is opposite to the earth. The time interval after which it can be seen at the same place when the sense of rotation of the earth and the satellite is the same will be
$8 h$
$24 h$
$12 h$
$6 h$

The time period is given by,
$T = \frac{2 π}{ω}$
Angular Velocity is given by,
$ω = \frac{2 π}{T}$
and then find relative angular velocity
Given $8 = \frac{2 π}{ω_{1} + ω_{2}} = \frac{2 π}{\frac{2 π}{T_{1}} + \frac{2 π}{T_{2}}}$

A satellite is seen after each 8h over the equator at a place on the earth when its sense of rotation is opposite to the earth. The time interval after which it can be seen at the same place when the sense of rotation of the earth and the satellite is the same will be8h24h12h6h

The time period is given by,T=2πωAngular Velocity is given by,ω=2πTand then find relative angular velocityGiven 8=2πω1+ω2=2π2πT1+2πT2

A satellite is seen after each $8 h$ over the equator at a place on the earth when its sense of rotation is opposite to the earth. The time interval after which it can be seen at the same place when the sense of rotation of the earth and the satellite is the same will be
$8 h$
$24 h$
$12 h$
$6 h$

The time period is given by,
$T = \frac{2 π}{ω}$
Angular Velocity is given by,
$ω = \frac{2 π}{T}$
and then find relative angular velocity
Given $8 = \frac{2 π}{ω_{1} + ω_{2}} = \frac{2 π}{\frac{2 π}{T_{1}} + \frac{2 π}{T_{2}}}$