A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :

−2mgR

−2mgR3

−mgR2

−mgR3

A

−2mgR3

B

−2mgR

C

−mgR2

D

−mgR3

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Solution

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Gravitational potential energy at distance r from the center of the earth is given as,

P=−GMEmr=−GMEm3R=−GMEm(R/3)R2

⟹P=−mgR3

Option D is correct.

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