A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :

Name: A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :
Uploaded: 2020-01-06
Description: Click here👆to get an answer to your question ✍️ A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :

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Answer 1

Gravitational potential energy at distance $r$ from the center of the earth is given as,
$P = - \frac{G M _{E} m}{r} = - \frac{G M _{E} m}{3 R} = - \frac{G M _{E} m ( R / 3 )}{R ^{2}}$

$⟹ P = - m g \frac{R}{3}$
Option D is correct.

Answer 2

Gravitational potential energy at distance

r

from the center of the earth is given as,

P = - \frac{G M _{E} m}{r} = - \frac{G M _{E} m}{3 R} = - \frac{G M _{E} m ( R / 3 )}{R ^{2}}

⟹ P = - m g \frac{R}{3}

Option D is correct.

A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :

$- 2 m g R$

$- m g \frac{R}{2}$

$- 2 m g \frac{R}{3}$

$- m g \frac{R}{3}$

Gravitational potential energy at distance $r$ from the center of the earth is given as,
$P = - \frac{G M _{E} m}{r} = - \frac{G M _{E} m}{3 R} = - \frac{G M _{E} m ( R / 3 )}{R ^{2}}$

$⟹ P = - m g \frac{R}{3}$
Option D is correct.

At perihelion, the gravitational potential energy of Pluto in its orbit has

An object is taken to height 2R above the surface of earth, the increase in potential energy is [R is radius of earth]

Two satellites of the same mass are launched in the same orbit around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after a collision is?

A body of mass 'm' is raised to a height $^{'} 10 R^{'}$ from the surface of earh, where 'R' is the radius of earth. The increase in potential energy is (G $=$ universal constant of gravitation, M $=$ mass of earth and g $=$ acceleration due to gravity).

Revise with Concepts

Gravitational Potential

Gravitational Potential Energy

Gravitational Potential Energy- Medium

Potential Energy Between Two Point Masses and System of Point Masses

Changing Configuration of a System

Gravitational Potential Energy - L2

A satellite of mass m is orbiting around the earth at a height equal to twice the radius of the earth (R). Its potential energy is given by :

−2mgR

−mg2R​

−2mg3R​

−mg3R​

Gravitational potential energy at distance r from the center of the earth is given as,P=−rGME​m​=−3RGME​m​=−R2GME​m(R/3)​ ⟹P=−mg3R​Option D is correct.

At perihelion, the gravitational potential energy of Pluto in its orbit has

An object is taken to height 2R above the surface of earth, the increase in potential energy is [R is radius of earth]

Two satellites of the same mass are launched in the same orbit around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after a collision is?

A body of mass 'm' is raised to a height ′10R′ from the surface of earh, where 'R' is the radius of earth. The increase in potential energy is (G= universal constant of gravitation, M=mass of earth and g= acceleration due to gravity).

Revise with Concepts

Gravitational Potential

Gravitational Potential Energy

Gravitational Potential Energy- Medium

Potential Energy Between Two Point Masses and System of Point Masses

Changing Configuration of a System

Gravitational Potential Energy - L2

$- 2 m g R$

$- m g \frac{R}{2}$

$- 2 m g \frac{R}{3}$

$- m g \frac{R}{3}$

Gravitational potential energy at distance $r$ from the center of the earth is given as,
$P = - \frac{G M _{E} m}{r} = - \frac{G M _{E} m}{3 R} = - \frac{G M _{E} m ( R / 3 )}{R ^{2}}$

$⟹ P = - m g \frac{R}{3}$
Option D is correct.

A body of mass 'm' is raised to a height $^{'} 10 R^{'}$ from the surface of earh, where 'R' is the radius of earth. The increase in potential energy is (G $=$ universal constant of gravitation, M $=$ mass of earth and g $=$ acceleration due to gravity).