Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

A schematic representation of enthalpy changes for the reaction, $C_{g r a p h i t e}$ + $\frac{1}{2} O_{2}$ (g) $\to$ CO (g) is given below. The missing value is

+ 10.5 kJ
- 11.05 kJ
- 110.5 kJ
- 10.5 kJ

A

- 11.05 kJ

B

+ 10.5 kJ

C

- 110.5 kJ

D

- 10.5 kJ

Open in App

Solution

Verified by Toppr

Since enthalpy is a state function therefore it does not depend on the path . Thats y the enthalpy of direct method and indirect method of formation of product ( i . e here CO2 ) will be same so thats y.....

-393.5 = X + (-283 KJ)

X = -110.5 KJ

Hence, the correct option is $C$

Was this answer helpful?

4

Similar Questions

Q1

A schematic representation of enthalpy changes for the reaction,

C_{g r a p h i t e}

+

\frac{1}{2} O_{2}

(g)

\to

CO (g) is given below. The missing value is

View Solution

Q2

Given :

C (g r a p h i t e) + \frac{1}{2} O_{2} \to C O Δ H_{1} = - 110.5 k J / m o l

C O + \frac{1}{2} O_{2} \to C O_{2} Δ H = - 283.2 k J / m o l

The heat of reaction (in

k J / m o l

) for the following reaction is:

C (g r a p h i t e) + O_{2} \to C O_{2} Δ H = ?

View Solution

Q3

Following are the thermochemical reactions:

C

(graphite)

+ \frac{1}{2} O_{2} \to C O; Δ H = - 110.5

kJ/mol

C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 283.2

kJ/mol

The heat of reaction (in kJ/mol) for the following reaction is:

C (graphite) + O_{2} \to C O_{2}

View Solution

Q4

The

Δ_{f} H^{o}

for the

C O_{2} (g), C O (g)

and

H_{2} O (l)

are -393.5, -110.5 and -241.8

k J m o l^{- 1}

respectively. The standard enthalpy change (in

k J m o l^{- 1}

) for the given reaction is :

C O_{2} (g) + H_{2} (g) \to C O (g) + H_{2} O (l)

View Solution

Q5

The

Δ_{f} H^{\circ}

for

C O_{2} (g), C O (g) a n d H_{2} O (g)

are

- 393.5, - 110.5

and

- 241.8 k J m o l^{- 1}

respectively. The standard enthalpy change (in kJ) for the reaction is:

C O_{2} (g) + H_{2} (g) ⟶ C O (g) + H_{2} O (g)

View Solution