A series LCR circuit with R - 20 Omega - L - 1-5 H and C - 35 muF is connected to a variable-frequency 200 V ac supply- When the frequency of the supply equals the natural frequency of the circuit- what is the average power transferred to the circuit in one complete cycle-

Question

Toppr Admin · Accepted Answer

At resonance- the frequency of supply power equals to naturan frequency of LCR circuit-Impedence- Z-x221A-R2-x3C9-L-x2212-1-x3C9-C-x3C9-L-1-x3C9-C-so- Z-RI-V-R-200-20-10-xA0-APower- W-V-xD7-I-200-xD7-10-2000-xA0-W

A series LCR circuit with R = 20 $Ω$ , L = 1.5 H and C = 35 $μ$ F is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?

At resonance, the frequency of supply power equals to naturan frequency of LCR circuit.
Impedence, $Z = \sqrt{R^{2} + (ω L - 1 / ω C)}$
$ω_{L} = \frac{1}{ω_{C}}$

so, $Z = R$
$I = V / R = 200 / 20 = 10 A$
Power, $W = V \times I = 200 \times 10 = 2000 W$

A series LCR circuit with R = 20 Ω , L = 1.5 H and C = 35 μF is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?

At resonance, the frequency of supply power equals to naturan frequency of LCR circuit.Impedence, Z=√R2+(ωL−1/ωC)ωL=1ωC so, Z=RI=V/R=200/20=10 APower, W=V×I=200×10=2000 W

A series LCR circuit with R = 20 $Ω$ , L = 1.5 H and C = 35 $μ$ F is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?

At resonance, the frequency of supply power equals to naturan frequency of LCR circuit.
Impedence, $Z = \sqrt{R^{2} + (ω L - 1 / ω C)}$
$ω_{L} = \frac{1}{ω_{C}}$

so, $Z = R$
$I = V / R = 200 / 20 = 10 A$
Power, $W = V \times I = 200 \times 10 = 2000 W$