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Question

A short bar magnet of magnetic moment 0.4JT1 is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is
  1. -0.064 J
  2. 0.082 J
  3. zero
  4. 0.064 J

A
0.064 J
B
zero
C
0.082 J
D
-0.064 J
Solution
Verified by Toppr

Potential energy of a magnet with magnetic moment M placed in a magnetic field B is given by
U=M.vecB
=MBcosθ
which is smallest for θ=0
Hence Umin=MB=0.4×0.16J
=0.064J

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