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# A short bar magnet of magnetic moment 0.4JT1 is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is-0.064 J0.082 Jzero0.064 J

A
0.064 J
B
zero
C
0.082 J
D
-0.064 J
Solution
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#### Potential energy of a magnet with magnetic moment →M placed in a magnetic field →B is given by U=−→M.vecB=−MBcosθwhich is smallest for θ=0Hence Umin=−MB=−0.4×0.16J=−0.064J

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