A short bar magnet of magnetic moment 0-4 J T-1- is placed in a uniform magnetic field of 0-16 T- The magnet is in stable equilibrium when the potential energy is-0-064 J0-082 Jzero0-064 J

Question

Toppr Admin · Accepted Answer

Potential energy of a magnet with magnetic moment -x2192-M placed in a magnetic field -x2192-B is given by-xA0-U-x2212-x2192-M-vecB-x2212-MBcos-x3B8-which is smallest for -x3B8-0Hence Umin-x2212-MB-x2212-0-4-xD7-0-16J-x2212-0-064J

A short bar magnet of magnetic moment $0.4 J T^{1}$ is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is
-0.064 J
0.082 J
zero
0.064 J

Potential energy of a magnet with magnetic moment $\to M$ placed in a magnetic field $\to B$ is given by
$U = - \to M . v e c B$
$= - M B c o s θ$
which is smallest for $θ = 0$
Hence $U_{m i n} = - M B = - 0.4 \times 0.16 J$
$= - 0.064 J$

A short bar magnet of magnetic moment 0.4JT1 is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is-0.064 J0.082 Jzero0.064 J

Potential energy of a magnet with magnetic moment →M placed in a magnetic field →B is given by U=−→M.vecB=−MBcosθwhich is smallest for θ=0Hence Umin=−MB=−0.4×0.16J=−0.064J

A short bar magnet of magnetic moment $0.4 J T^{1}$ is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is
-0.064 J
0.082 J
zero
0.064 J

Potential energy of a magnet with magnetic moment $\to M$ placed in a magnetic field $\to B$ is given by
$U = - \to M . v e c B$
$= - M B c o s θ$
which is smallest for $θ = 0$
Hence $U_{m i n} = - M B = - 0.4 \times 0.16 J$
$= - 0.064 J$