A short bar Magnet with its north pole facing North forms a neutral point P in the horizontal plane. If the magnet is rotated by 90 $^{0}$ in the horizontal plane, the net magnetic induction at P is:
(Horizontal component of earths magnetic field is $B_{H}$ )

Question

A short bar Magnet with its north pole facing North forms a neutral point P in the horizontal plane. If the magnet is rotated by 90 $^{0}$ in the horizontal plane, the net magnetic induction at P is:
(Horizontal component of earths magnetic field is $B_{H}$ )

Toppr Admin · Accepted Answer

At P- the equatorial-xA0-field due to magnet -BH-After rotation- P lies on the axis of the bar magnet-Hence- at P- field due to magnet -2BHNet field is the vector sum of BH and 2BH- both at right angles to each other giving- Bnet-x221A-5BH

A short bar Magnet with its north pole facing North forms a neutral point P in the horizontal plane. If the magnet is rotated by 900 in the horizontal plane, the net magnetic induction at P is:(Horizontal component of earths magnetic field is BH)

At P, the equatorial field due to magnet =BH.After rotation, P lies on the axis of the bar magnet.Hence, at P, field due to magnet =2BHNet field is the vector sum of BH and 2BH, both at right angles to each other giving, Bnet=√5BH

A short bar Magnet with its north pole facing North forms a neutral point P in the horizontal plane. If the magnet is rotated by 90 $^{0}$ in the horizontal plane, the net magnetic induction at P is:
(Horizontal component of earths magnetic field is $B_{H}$ )

At P, the equatorial field due to magnet $= B_{H}$ .
After rotation, P lies on the axis of the bar magnet.
Hence, at P, field due to magnet $= 2 B_{H}$
Net field is the vector sum of $B_{H}$ and $2 B_{H}$ , both at right angles to each other giving, $B_{n e t} = \sqrt{5} B_{H}$