A short bar Magnet with its north pole facing North forms a neutral point P in the horizontal plane. If the magnet is rotated by 900 in the horizontal plane, the net magnetic induction at P is:
(Horizontal component of earths magnetic field is BH)
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At P, the equatorial field due to magnet =BH. After rotation, P lies on the axis of the bar magnet.
Hence, at P, field due to magnet =2BH Net field is the vector sum of BH and 2BH, both at right angles to each other giving, Bnet=√5BH
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A short bar magnet is placed in the magnetic meridian of earth with its north pole pointing towards North. Neutral points are found at a distance of 30cm from the magnet on the East-West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is approximately equal to _____(Given μ04π=10−7 in SI units and BH = Horizontal component of earth's magnetic field = 3.6×10−5 tesla)
A short bar magnet is kept in the earth's magnetic field with its north pole pointing geographic north. The magnetic moment of the short bar magnet is 0.4Am2. If earth's horizontal magnetic field is 4×10−5T, then the distance between the null points is
A short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East - West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is close to (Given μ04π=10−7 in SI units and BH= Horizontal component of earth's magnetic field =3.6×10−5Tesla.)
Assertion :A compass needle when placed on the magnetic north pole of the earth rotates in vertical direction. Reason: The earth has only horizontal component of its magnetic field at the north pole.
A bar magnet of magnetic moment 0.4Am2 is placed in the magnetic meridian with its north pole pointing north. A neutral point is obtained at a distance of 10cm from the centre of the magnet.If the length of the magnet is 20cm, then the value of horizontal component of earth magnetic induction is: