A simple harmonic oscillator of angular frequency 2 rad s−1 is acted upon by an external force F=sintN. If the oscillator is at rest in its equilibrium position at t=0, its position at later times is proportional to
sint+12cos2t
cost−12sin2t
sint−12sin2t
sint+12sin2t
A
sint−12sin2t
B
cost−12sin2t
C
sint+12sin2t
D
sint+12cos2t
Open in App
Solution
Verified by Toppr
Was this answer helpful?
0
Similar Questions
Q1
A simple harmonic oscillator of angular frequency 2 rad/s is acted upon by an external force F=sint N. If the oscillator is at rest in its equilibrium position at t=0, its position at later times is proportional to:
View Solution
Q2
A simple harmonic oscillator of angular frequency 2rads−1 is acted upon by an external force F=sintN. If the oscillator is at rest in its equilibrium position at t=0, its position at later times is proportional to
View Solution
Q3
If a curve is given by x=acost+b2cos2t and y=sint+b2sin2t, then the points for which d2ydx2=0, are given by.
View Solution
Q4
At time t=0, the displacement of a simple harmonic oscillator from the mean position is 0.2m and the velocity is 0.5m/s. What is the amplitude of oscillator if angular frequency is 2πrad/s.
View Solution
Q5
If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0ms−1 at any time, the angular frequency of the oscillator is equal to