Question

A simple pendulum completes 40 oscillation in a minute .Find its (a) frequency (b) time period.

Answer 1

Given

Number of Oscillations, $N=40$

Time $t=1min$

Frequency $f=\frac{N}{t}=\frac{40}{60}=0.667Hz$

Time period,$T=\frac{1}{f}=1.5\sec$

Hence, frequency is $0.667Hz$ and time period is $1.5\sec$