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>> $A simple pendulum completes 40 oscillati$

Question

A simple pendulum completes 40 oscillation in a minute .Find its (a) frequency (b) time period.

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Updated on : 2022-09-05

Solution

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Given

Number of Oscillations, $N = 40$

Time $t = 1 min$

Frequency $f = \frac{N}{t} = \frac{4 0}{6 0} = 0.667 H z$

Time period, $T = \frac{1}{f} = 1.5 sec$

Hence, frequency is $0.667 H z$ and time period is $1.5 sec$

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