Question

A simple pendulum has a time period T1 when on the earth's surface and T2 when taken to a height R above the earth's surface, where R is the radius of the earth. The value of T2T1 is:

A
1
B
2
C
4
D
2
Solution
Verified by Toppr

Time period of a simple pendulum =2πlg
g on earth's surface =GMR2
g on a height R above earth's surface =GM(2R)2
T1 (time period on earth's surface ) =2πl(R2)GM
T2 (time period at a height h above earth's surface ) =2πl(2R)2GM
T2T1=4=2.
Hence, the answer is 2.



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