A simple pendulum is oscillating with an angular amplitude $60^{0}$ . If mass of bob is $50 g r a m$ , the tension in the string at mean position is:
$(g = 10 m / s^{2})$

Question

A simple pendulum is oscillating with an angular amplitude 60-0- If mass of bob is 50 gram- the tension in the string mean position is-g-10 m-s-2-0-5 N1-5 N1 N2 N

Toppr Admin · Accepted Answer

H-R-1-x2212-cos-xA0-600-H-R2Apply Work Energy Theorem-

A simple pendulum is oscillating with an angular amplitude $60^{0}$ . If mass of bob is $50 g r a m$ , the tension in the string at mean position is:
$(g = 10 m / s^{2})$
$0.5 N$
$1.5 N$
$1 N$
$2 N$

$H = R (1 - c o s 60^{0})$

$H = \frac{R}{2}$

Apply Work Energy Theorem,

A simple pendulum is oscillating with an angular amplitude 600. If mass of bob is 50 gram, the tension in the string at mean position is:(g=10 m/s2)0.5 N1.5 N1 N2 N

H=R(1−cos 600)H=R2Apply Work Energy Theorem,

A simple pendulum is oscillating with an angular amplitude $60^{0}$ . If mass of bob is $50 g r a m$ , the tension in the string at mean position is:
$(g = 10 m / s^{2})$
$0.5 N$
$1.5 N$
$1 N$
$2 N$

$H = R (1 - c o s 60^{0})$

$H = \frac{R}{2}$

Apply Work Energy Theorem,