A simple pendulum is oscillating with an angular amplitude $60^{o}$ . If $m$ is mass of bob and $T_{1}$ , $T_{2}$ are tensions in the string, when the bob is at extreme position, mean position respectively then is:
A) $T_{1} = \frac{m g}{2}$
B) $T_{2} = 2 m g$
C) $T_{1} = 0$
D) $T_{2} = 3 m g$

Question

A simple pendulum is oscillating with an angular amplitude

60^{o}

. If

m

is mass of bob and

T_{1}

,

T_{2}

are tensions in the string, when the bob is at extreme position, mean position respectively then is:

A)

T_{1} = \frac{m g}{2}

B)

T_{2} = 2 m g

C)

T_{1} = 0

D)

T_{2} = 3 m g

Toppr Admin · Accepted Answer

At ATA-mgcos600TA-mg2By Work Energy Theorem from A to BmgR-1-x2212-cos600-12mV2mgR2-12mV2V-x221A-RgAt BTB-x2212-mg-mV2RTB-mg-mg-2mg-x2234-TBTA-2mgmg-2-4

A simple pendulum is oscillating with an angular amplitude 60∘. The ratio of tensions in the string when the bob reaches the mean position and the extreme position respectively is :2:11:33:14:1

At ATA=mgcos600TA=mg2By Work Energy Theorem from A to BmgR(1−cos600)=12mV2mgR2=12mV2V=√RgAt BTB−mg=mV2RTB=mg+mg=2mg∴TBTA=2mgmg/2=4

A simple pendulum is oscillating with an angular amplitude $60^{\circ}$ . The ratio of tensions in the string when the bob reaches the mean position and the extreme position respectively is :
$2 : 1$
$1 : 3$
$3 : 1$
$4 : 1$