A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor but has thickness 3d/4, where d is the distance between plates. How is the capacitors changed when the slab is inserted between the plates?
Medium
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Updated on : 2022-09-05
Solution
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C=dAϵ0
C′=d−t+ktAϵ0
Put t=43d ;
C′=3+k4k.dAϵ0
C′=3+k4k.C
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