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Question

A slow neutron strikes a nucleus of 23592U splitting it into lighter nuclei of 14156Ba and 9236Kr along with three neutrons. The energy released in this reaction is :
(The masses of Uranium, Barium and Krypton in this reaction are 235.043933,140.917700 and 91.895400 amu respectively. The mass of a neutron is 1.008665 amu)
  1. 198.87 MeV
  2. 156.9 MeV
  3. 186.9 MeV
  4. 196.9 MeV

A
156.9 MeV
B
198.87 MeV
C
186.9 MeV
D
196.9 MeV
Solution
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23592U+1n14156Ba+9236Kr+31n

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