A small circle ring has a uniform charge distribution. On a far-off axial point distance x from the centre of the ring, the electric field is proportional to:
x−1
x−3/2
x−2
x5/4
A
x−2
B
x−1
C
x5/4
D
x−3/2
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Solution
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Electronic field due to a charged ring in given by :-
at point p
∣∣→E∣∣=KQx(R2+x2)3/2Q=λ(2πr)
at a large distance, x≫R, so :- R2+x2≃x2
⇒∣∣→E∣∣=K&x(x2)3/2=KQx2=Eαx−2
so at large distance, ring behave an a point particle.
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