A small mass m starts from rest and slides down the smooth spherical
surface of Radius R. Assume zero potential energy at the top. Find the speed of the mass as a function of the angle θ made by the radius through the mass with the vertical.
v=√2gR(1+cosθ)
v=√2gR(1−cosθ)
v=√2gRcosθ
v=√2gR(1−sinθ)
A
v=√2gR(1+cosθ)
B
v=√2gR(1−sinθ)
C
v=√2gR(1−cosθ)
D
v=√2gRcosθ
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Solution
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Loss in potential energy is converted into the kinetic energy, 12mv2=mgR(1−cosθ) v=√2gR(1−cosθ)
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