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Question

A small mass m starts from rest and slides down the smooth spherical surface of Radius R. Assume zero potential energy at the top. Find the speed of the mass as a function of the angle θ made by the radius through the mass with the vertical.
  1. v=2gR(1+cosθ)
  2. v=2gR(1cosθ)
  3. v=2gRcosθ
  4. v=2gR(1sinθ)

A
v=2gR(1+cosθ)
B
v=2gR(1sinθ)
C
v=2gR(1cosθ)
D
v=2gRcosθ
Solution
Verified by Toppr

Loss in potential energy is converted into the kinetic energy,
12mv2=mgR(1cosθ)
v=2gR(1cosθ)

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