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A small object is embedded in a glass sphere (μ=1.5) of radius 5.0 cm at a distance 1.5 cm left to the centre. Locate the image of the object as seen by an observer standing to the left of the sphere?

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Solution

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We know,

μairv−μglassu=μair−μglassR

Here,

The radius of the glass sphere (R) is 5 cm, and the object distance is u=−(5−1.5)=−3.5 cm

We put the values in the formula and get-

1v−1.5−3.5=1−1.5−5

1v+37=−0.5−5

1v+37=110

1v=110−37=7−3070

1v=7−3070=−2170

Therefore, v=7021≈3 cm from the surface of the glass sphere and the image of the object as seen by an observer standing to the left of the sphere will be at 2 cmleft to the center.

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