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# A small object is embedded in a glass sphere (μ=1.5) of radius 5.0 cm at a distance 1.5 cm left to the centre. Locate the image of the object as seen by an observer standing to the left of the sphere?1 cm left to the centre1 cm right to the centre2 cm right to the centre2 cm left to the centre

A
1 cm left to the centre
B
2 cm right to the centre
C
2 cm left to the centre
D
1 cm right to the centre
Solution
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#### We know,μairv−μglassu=μair−μglassRHere, The radius of the glass sphere (R) is 5 cm, and the object distance is u=−(5−1.5)=−3.5 cmWe put the values in the formula and get-1v−1.5−3.5=1−1.5−51v+37=−0.5−51v+37=1101v=110−37=7−30701v=7−3070=−2170Therefore, v=7021≈3 cm from the surface of the glass sphere and the image of the object as seen by an observer standing to the left of the sphere will be at 2 cmleft to the center.

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