A small roller coaster starts point A with a speed u on a curved track as shown in the figure-The friction between the roller coaster and the track is negligible and its always remains in contact with the track- The speed of roller coaster point D on the track will be-u-2- - 2gh-1-2-u-2- - gh-1-2-u-2- - 4gh-1-2-u

Question

Toppr Admin · Accepted Answer

Let the speed of the roller coaster at point D be v-Applying the law of conservation of energy between points A and D- we get12mu2-mg-2h-12mv2-0or u2-4gh-v2 or v-x221A-u2-4gh-

Let the speed of the roller coaster at point D be v.Applying the law of conservation of energy between points A and D, we get12mu2+mg(2h)=12mv2+0or u2+4gh=v2 or v=√u2+4gh.

Let the speed of the roller coaster at point $D$ be $v$ .
Applying the law of conservation of energy between points $A$ and $D$ , we get
$\frac{1}{2} m u^{2} + m g (2 h) = \frac{1}{2} m v^{2} + 0$
or $u^{2} + 4 g h = v^{2}$ or $v = \sqrt{u^{2} + 4 g h}$ .