A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are respectively:
$H_{2}, O_{2}$
$O_{2}, N a$
$O_{2}, H_{2}$
$O_{2}, S O_{2}$

Question

A solution of sodium sulphate in water is electrolysed using inert electrodes- The products the cathode and anode are respectively-H-2- -O-2-O-2- Na-O-2- -H-2-O-2- -SO-2-

Toppr Admin · Accepted Answer

A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are $H_{2}$ , $O_{2}$ respectively.
Hydrogen ions having lower discharge (or higher reduction) potential than sodium ions will be liberated at the cathode.
$2 H^{+} + 2 e^{-} \to H_{2} ↑$
Hydroxide ions having a lower discharge potential than sulphate ions, will be liberated at anode.
$4 O H^{-} \to 2 H_{2} O + O_{2} + 4 e^{-}$

A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are respectively:H2, O2O2, NaO2, H2O2, SO2

A solution of sodium sulphate in water is electrolysed using inert electrodes. The products at the cathode and anode are respectively:
$H_{2}, O_{2}$
$O_{2}, N a$
$O_{2}, H_{2}$
$O_{2}, S O_{2}$