A sphere of diameter 6 cm is dropped in a right circular cylindrical vessel partly filled with water. The diameter of the cylindrical vessel is 12 cm. If the sphere is completely submerged in water, by how much will the level of water rise in the cylindrical vessel?
sphere diameter =6 cm
radius of sphere =d2=3 cm=R
→ diameter of cylinder d=12 cm
radius of cylinder =122=6 cm=R
→ sphere is submerge in cylinder, so,
volume of the water required in the vessel
= volume of sphere
∴ π R2.h=43πr3
∴ h=43×r3×1R2
=43×(3)3×1(6)2
∴ h=1 cm