A sphere of mass 50 kg is attached by a second sphere of mass 90 kg with a force equal to a weight of 0-5 mg and their centres are 20 cm apart- The gravitational constant is-4-2 times 10-11- Nm-2kg-2-4-4 times 10-11- Nm-2kg-2-3-3 times 10-11- Nm-2kg-2-6-23 times 10-15- Nm-2kg-2-

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Toppr Admin · Accepted Answer

F-Gm1m2r2F-0-5-xD7-10-x2212-6-9-8-N-5-xD7-10-x2212-6-9-8-G-50-90-0-22-x27F9-G-4-4-xD7-10-x2212-11Nm2kg2

A sphere of mass 50kg is attached by a second sphere of mass 90kg with a force equal to a weight of 0.5mg and their centres are 20cm apart. The gravitational constant is.4.2×10−11Nm2kg24.4×10−11Nm2kg23.3×10−11Nm2kg26.23×10−15Nm2kg2

F=Gm1m2r2F=0.5×10−6(9.8)N.5×10−6(9.8)=G(50)(90)(0.22)⟹G=4.4×10−11Nm2kg2

$F = \frac{G m_{1} m_{2}}{r^{2}}$

$F = 0.5 \times 10^{- 6} (9.8) N$

$.5 \times 10^{- 6} (9.8) = \frac{G (50) (90)}{({0.2}^{2})}$

$⟹ G = 4.4 \times 10^{- 11} N m^{2} k g^{2}$