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Question

- R
- 3R
- 2R
- 5R

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Solution

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Let us assume

OP = PQ = a (say)

According to sign conventions,

Object distance (u) = -x

Image distance (v) = +x

We know the formula

μ2v - μ1u = μ2 - μ1R

Substituting the values in the above formula,

1.5x - 1 - x = 1.5 - 1R

1.5x + 1x = 0.5 R

2.5x = 0.5 R

x = 5R

The distance PO is equal to 5R.

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