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A spring of force constant k is cut into
Question
A spring of force constant
k
is cut into lengths of ratio
1
:
2
:
3
. They are connected in series and the new force constant is
k
′
. Then they are connected in parallel and force constant is
k
′
′
. Then
k
′
:
k
′
′
is:
A
1
:
1
4
B
1
:
6
C
1
:
9
D
1
:
1
1
Medium
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Solution
Verified by Toppr
Correct option is D)
spring in series
k
′
1
=
k
1
+
2
k
1
+
3
k
1
→
k
′
=
1
1
6
k
k
"
=
k
+
2
k
+
5
k
=
6
k
k
"
k
′
=
6
k
1
1
6
k
=
1
1
1
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