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Question

A spring of force constant k is cut into lengths of ratio 1:2:3. They are connected in series and the new force constant is k. Then they are connected in parallel and force constant is k′′. Then k:k′′ is:
  1. 1:14
  2. 1:6
  3. 1:9
  4. 1:11

A
1:14
B
1:11
C
1:6
D
1:9
Solution
Verified by Toppr

spring in series
1k=1k+12k+13kk=6k11

k"=k+2k+5k=6k
kk′′=6k116k = 111

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