Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

A spring of force constant $k$ , is cut into two equal parts, then the force constant of each piece is :
$k$
$k / 2$
$4 / k$
$2 k$

A

k

B

k / 2

C

4 / k

D

2 k

Open in App

Solution

Verified by Toppr

$k = \frac{E A}{l}$
When cut to two equal halves, new length $l_{1}$ becomes $l / 2$
$k_{1} = \frac{E A}{l_{1}} = \frac{2 E A}{l} = 2 k$

Was this answer helpful?

0

Similar Questions

Q1

A spring of force constant

k

, is cut into two equal parts, then the force constant of each piece is :

View Solution

Q2

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of :

View Solution

Q3

A spring of force constant

k

is cut into two equal parts, which are then joined parallel to each other. The force constant of the combination will be

View Solution

Q4

A spring of force constant k is cut into two equal halves. The force constant of each half is

View Solution

Q5

A spring of force constant

K

is cut into two pieces such that one piece is double the length of the- other, then find out the force constant of the longer piece

(K = 6 N / m)

in

N / m

.

View Solution