A spring of force constant K is into two pieces such that the one piece is double the length of the other- Then the long piece will have a force constant of-2-3- K3-2 K3K6K

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-Force constant- K-x221D-1l-clLet the spring cut into pieces-of length x-2xSo- x-2x-l-x21D2-x-l3Force constant of long piece is- k-x2032-c2x-Kl2l-3-3K2

A spring of force constant $K$ is cut into two pieces such that the one piece is double the length of the other. Then the long piece will have a force constant of:
$(2 / 3) K$
$3 / 2 K$
$3 K$
$6 K$

Force constant, $K \propto \frac{1}{l} = \frac{c}{l}$
Let the spring cut into pieces of length $x, 2 x$
So, $x + 2 x = l \Rightarrow x = \frac{l}{3}$
Force constant of long piece is: $k^{'} = \frac{c}{2 x} = \frac{K l}{2 l / 3} = \frac{3 K}{2}$

A spring of force constant K is cut into two pieces such that the one piece is double the length of the other. Then the long piece will have a force constant of:(2/3) K3/2 K3K6K

Force constant, K∝1l=clLet the spring cut into pieces of length x,2xSo, x+2x=l⇒x=l3Force constant of long piece is: k′=c2x=Kl2l/3=3K2

A spring of force constant $K$ is cut into two pieces such that the one piece is double the length of the other. Then the long piece will have a force constant of:
$(2 / 3) K$
$3 / 2 K$
$3 K$
$6 K$

Force constant, $K \propto \frac{1}{l} = \frac{c}{l}$
Let the spring cut into pieces of length $x, 2 x$
So, $x + 2 x = l \Rightarrow x = \frac{l}{3}$
Force constant of long piece is: $k^{'} = \frac{c}{2 x} = \frac{K l}{2 l / 3} = \frac{3 K}{2}$